\(\frac{{dn}}{{dt}} = \frac{{Id.A}}{E} \Rightarrow \frac{{dn}}{{dt}} \propto \frac{1}{{{d^2}}}\)
\(\frac{{{{\left( {\frac{{dn}}{{dt}}} \right)}_1}}}{{{{\left( {\frac{{dn}}{{dt}}} \right)}_2}}} = \frac{{d_1^2}}{{d_1^2}} = 4\)
(Assume $\mathrm{h}=6.63 \times 10^{-34} \mathrm{~J} \mathrm{~s}, \mathrm{~m}_{\mathrm{e}}=9.0 \times 10^{-31} \mathrm{~kg}$ અને $\mathrm{m}_{\mathrm{p}}=1836$ $x$ $\mathrm{m}_{\mathrm{e}}$ ધારો)