${C_{\left( {graphite} \right)}} + {O_{2\left( g \right)}} \to C{O_{2\left( g \right)}}\,;\,\Delta H = -393.5\,kJ$
${C_2}{H_{4\left( g \right)}} + 3{O_{2\left( g \right)}} \to 2C{O_{2\left( g \right)}} + 2{H_2}{O_{\left( l \right)}}\,;\,\Delta H = - 1410.9\,kJ$
${H_{2\left( g \right)}} + 1/2{O_{2\left( g \right)}} \to {H_2}{O_{\left( l \right)}}\,;\,\Delta H = - 285.8\,kJ$
\(ii)\) \(C _2 H _4+3 O _2 \longrightarrow 2 CO _2+2 H _2 O \quad \Delta H _{ ii }=-1410.9\)
\(iii)\) \(H _2+\frac{1}{2} O _2 \longrightarrow H _2 O \quad \Delta I _{ iii }=-25.8\)
\(iv)\) \(2 C +2 H _2 \longrightarrow C _2 H _4 \Delta H =(?)\)
\(iv)\) \(=2( i )-( ii )+2 (iii)\)
\(\therefore \Delta H =2 \Delta H _{ i }-2 \Delta H _{ ii }+2 \Delta H _{ iii }\)
\(=2(-393.5)-(-1410.9)+2(-285.8)\)
\(=-787+1410.9-571.6\)
\(=1410.9-1358.6\)
\(=52.3\, kJ\)
$H _{2( g )}+ Br _{2( g )} \rightarrow 2 HBr _{( g )}$
$H _{2}$ અને $H _{2}$ ની બંધઊર્જા અનુક્રમે $435\, kJ\, mol ^{-1}$ અને $192\, kJ mol\, ^{-1}$ છે. $HBr$ ની બંધઊર્જા ($kJ\, mol$ $^{-1}$ માં) જણાવો.