hence \(2.4 \times {10^{ - 5}} = 3.0 \times {10^{ - 5}}({N_2}{O_5})\)
or \(({N_2}{O_5})\) \( = 0.8\,\,mol\,\,{l^{ - 1}}\)
| $p ( mm Hg )$ | $50$ | $100$ | $200$ | $400$ |
| સાપેક્ષ $t _{1 / 2}( s )$ | $4$ | $2$ | $1$ | $0.5$ |
પ્રક્રિયાનો ક્રમ શોધો.
$(\log \,4 = 0.60,\, \log \,5 = 0.69)$
$N{H_2}N{O_{2\left( {aq} \right)}} + OH_{\left( {aq} \right)}^ - \to NHNO_{2\left( {aq} \right)}^ - + {H_2}{O_{\left( l \right)}}$
$NHNO_{2\left( {aq} \right)}^ - \to {N_2}{O_{\left( {aq} \right)}} + OH_{\left( {aq} \right)}^ - $