$H _{2( g )}+ Br _{2( g )} \rightarrow 2 HBr _{( g )}$
$H _{2}$ અને $H _{2}$ ની બંધઊર્જા અનુક્રમે $435\, kJ\, mol ^{-1}$ અને $192\, kJ mol\, ^{-1}$ છે. $HBr$ ની બંધઊર્જા ($kJ\, mol$ $^{-1}$ માં) જણાવો.
\(\Delta H =\sum( BE )_{ R }-\sum( BE )_{ P }\)
\(=\left(B E_{H-H}\right)+\left(B E_{B r-B r}\right)-2\left(B E_{H-B r}\right)\)
\(-109=(435)+(192)-2\left( BE _{ H - Br }\right)\)
\(BE _{ H - Br }=368 kJ mol ^{-1}\)
$3 HC \equiv CH _{( g )} \rightleftharpoons C _{6} H _{6(\ell)}$
[આપેલ : $\Delta_{f} G ^{\circ}( HC \equiv CH )=-2.04 \times 10^{5}\, J mol ^{-1}$
$\Delta_{f} G ^{\circ}\left( C _{6} H _{6}\right)=-1.24 \times 10^{5}\, J mol ^{-1} ; R =8.314\,\left. J K ^{-1} mol ^{-1}\right]$
$CCl _{4( g )} + 2 H _2 O ( g ) \rightarrow CO _{2( g )} + 4 HCl ( g )$
( $R=2.0 \mathrm{cal} \mathrm{K}^{-1} \mathrm{~mol}^{-1}$ આપેલ છે.)
(તટસ્થીકરણ એન્થાલ્પી $=57\, kJ \,mol ^{-1}$ અને પાણીની વિશિષ્ટ ઉષ્મા= $4.2 \,J\,K ^{-1} \,g ^{-1}$ )