$\Delta H = (B.E.)_{Reactant} - (B.E.)_{Product}$
$\Delta H = (B.E.)_{C = C} + 4(B.E.)_{C - H} + (B.E.)_{H - H} - (B.E.)_{C - C} - 6(B.E.)_{C - H}$
$\Delta H = 145 + 4 × 99 + 103 - 80 - 6 × 99$
= $-30\, Kcal \,mole^{-1}$
$2 A ( g ) \rightarrow A _{2}( g )$
$298\, K$ પર $\Delta U^ \ominus,=-20\, kJ\, mol ^{-1}, \Delta S \odot=-30\, J$$K ^{-1}\, mol ^{-1},$ પછી $\Delta G ^{\ominus}$ ........$J$ હશે?
${C_{\left( {graphite} \right)}} + {O_{2\left( g \right)}} \to C{O_{2\left( g \right)}}\,;\,\Delta H = -393.5\,kJ$
${C_2}{H_{4\left( g \right)}} + 3{O_{2\left( g \right)}} \to 2C{O_{2\left( g \right)}} + 2{H_2}{O_{\left( l \right)}}\,;\,\Delta H = - 1410.9\,kJ$
${H_{2\left( g \right)}} + 1/2{O_{2\left( g \right)}} \to {H_2}{O_{\left( l \right)}}\,;\,\Delta H = - 285.8\,kJ$
$PCl_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)}$
માટે નીચેનામાંથી કઈ શરત સાચી છે ?
$NH _{2} CN _{( s )}+\frac{3}{2} O _{2}( g ) \rightarrow N _{2( g )}+ O _{2}( g )+ H _{2} O _{(l)}$
$\Delta H _{298}$ ની માત્રા ........ $kJ$ છે. (નજીક પૂર્ણાંક રાઉન્ડ ઓફ)
[ધારી લો આદર્શ વાયુઓ અને $\left. R =8.314\, J\, mol ^{-1} K ^{-1}\right]$