$K = \frac{{2.303}}{t}\log \frac{{{{[R]}_0}}}{{{{[R]}_t}}}$
$K = \frac{{2.303}}{{2 \times {{10}^4}}}\log \frac{{800}}{{50}}$
$ = \frac{{2.303 \times \log {\mkern 1mu} {\mkern 1mu} 16}}{{2 \times {{10}^4}}}$
$ = 1.386{\mkern 1mu} \times {10^{ - 4}}{\mkern 1mu} $ સેકન્ડ $^{-1}$
( $\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}, \log 4=0.6021$ આપેલ છે.)
$A\,\xrightarrow{{{K_1}}}\,B,$ સક્રિયકરણ ઊર્જા ; $Ea_1$
$A\,\xrightarrow{{{K_2}}}\,C,$ સક્રિયકરણ ઊર્જા $Ea_2$