\(\frac{\mu_{2}}{v}-\frac{\mu_{1}}{u}=\frac{\mu_{2}-\mu_{1}}{R}\)
As per sign convention,
\(u=-x, v=+x, R\) is \(+v e\)
\(\mu_{1}=1, \mu_{2}=1.5\)
\(\therefore \frac{1.5}{x}-\frac{1}{-x}=\frac{1.5-1}{R}\)
or \(, \frac{1.5}{x}+\frac{1}{x}=\frac{0.5}{R}\) or \(\frac{2.5}{x}\)
\(=\frac{0.5}{R}\) or \(x=5 R\)
Distance \(P O=5 R\)
(શૂન્યવકાશમા પ્રકાશનો વેગ $=3 \times 10^{8} \,{m} / {s}$ અને $\left.\cos 30^{\circ}=\frac{\sqrt{3}}{2}\right)$