Question
Read the passage given below and answer the following questions:
The amines are basic in nature due to the presence of a lone pair of electron on N-atom of the -NH2 group, which it can donate to electron deficient compounds. Aliphatic amines are stronger bases than NH3 because of the +I effect of the alkyl groups. Greater the number of alkyl groups attached to N-atom, higher is the electron density on it and more will be the basicity. Thus, the order of basic nature of amines is expected to be 3º > 2º > 1º, however the observed order is 2º > 1º > 3º. This is explained on the basis of crowding on N-atom of the amine by alkyl groups which hinders the approach and bonding by a proton, consequently, the electron pair which is present on N is unavailable for donation and hence 3º amines are the weakest bases.
Aromatic amines are weaker bases than ammonia and aliphatic amines. Electron-donating groups such as -CH3, -OCH3, etc. increase the basicity while electron-withdrawing substitutes such as -NO2, -CN, halogens, etc. decrease the basicity of amines. The effect of these substituents is more at p than at m-positions.
The following questions are multiple choice questions. Choose the most appropriate answer:
  1. Which one of the following is the strongest base in aqueous solution?
  1. Methyl amine.
  2. Tri methyl amine.
  3. Aniline.
  4. Dimethyl amine.
  1. Which order ofbasicity is correct?
  1. Aniline > m-toluidine > o-toluidine
  2. Aniline> o-toluidine > m-toluidine
  3. o-toluidine > aniline> m-toluidine
  4. o-toluidine < aniline < m-toluidine
  1. What is the decreasing order of basicity of primary, secondary and tertiary ethylamines and NH3?
  1. NH3 > C2H5NH2 > (C2H5)2NH > (C2H5)3N
  2. (C2H5)3N > (C2H5)2NH > C2H5NH2 > NH3
  3. (C2H5)2NH > C2H5NH2> (C2H5)3N > NH3
  4. (C2H5)2NH > (C2H5)3N > C2H5NH2 > NH3
  1. The order of basic strength among the following amines in benzene solution is:
  1. CH3NH2 > (CH3)3N > (CH3)2NH
  2. (CH3)3N > (CH3)2NH > CH3NH2
  3. CH3NH2 > (CH3)2NH > (CH3)3N
  4. (CH3)3N > CH3NH2 > (CH3)2NH
  1. Choose the correct statement.
  1. Methylamine is slightly acidic.
  2. Methylamine is less basic than ammonia.
  3. Methylamine is a stronger base than ammonia.
  4. Methylamine forms salts with alkalies.

Answer

  1. (d) Dimethyl amine.

Explanation:

The increasing order of basicity of the given compounds is (CH3)2NH > CH3NH2 > (CH3)3N > C6H5NH2. Due to the +I effect of alkyl groups, the electron density on nitrogen increases and thus, the availability of the lone pair of electrons to proton increases and hence, the basicity of amines also increases. So, aliphatic amines are more basic than aniline. ln case of tertiary amine (CH3)3N, the covering of alkyl groups over nitrogen atom from all sides makes the approach and bonding by a proton relatively difficult, hence the basicity decreases. Electron withdrawing groups decrease electron density on nitrogen atom and thereby decreasing basicity.

  1. (d) o-toluidine < aniline < m-toluidine

Explanation:

In general, electron donating ( +R) group which when present on benzene ring (-NH2, -OR, -R, etc.) at the para position increases the basicity of aniline.

Ortho substituted anilines are weaker bases than aniline due to ortho effect.

  1. (d) (C2H5)2NH > (C2H5)3N > C2H5NH2 > NH3

Explanation:

In case of ethylamines, the combined effect of (c) inductive effect, steric effect and salvation effect gives the order of basic strength as

$(\text{C}_2\text{H}_5)_2\text{NH}>(\text{C}_2\text{H}_5)_3\text{N}>\text{C}_2\text{H}_5\text{NH}_2>\text{NH}_3\\\ \ \ \ \ \ \ \ (2^\circ)\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (3^\circ)\ \ \ \ \ \ \ \ \ \ \ \ \ (1^\circ)$

  1. (b) (CH3)3N > (CH3)2NH > CH3NH2

Explanation:

In non-aqueous solvents the basic strength of alkyl amines follows the order:

tertiary amines> secondary amines> primary amines.

  1. (c) Methylamine is a stronger base than ammonia.

Explanation:

Methyl amine is stronger base than ammonia due to electron releasing inductive effect of methyl group.

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When a chemical reaction involves bond cleavage or bond formation at an asymmetric carbon atom, three different products may be formed. For example, during the substitution of a group X by Y in the following reaction, the three possible products may be shown below:

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  2. Assertion and reason both are correct statements but reason is not correct explanation for assertion.
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  1. First member of ketos sugar is:
  1. Ketotriose.
  2. Ketotetrose.
  3. Ketopentose.
  4. Ketohexose.
  1. In CH2OHCHOHCHOHCHOHCHOHCHO, the number of optical isomers will be:
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  2. 8
  3. 32
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Among the above, correct statements are:

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  2. 3 and 4 only
  3. 1, 2 and 4 only
  4. 1, 2, 3 and 4
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  3. Pentaacetate of glucose does not react with hydroxylamine.
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  3. Sodium benzoate and sodium formate.
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  3. C6H5CHO
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  1. Assertion and reason both are correct statements and reason is correct explanation for assertion.
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  2. 1-chloro-2, 2-dimethyl butane.
  3. 1-chloro-2-methyl butane.
  4. 2-chloro-2-methyl butane.
  1. The reaction of (C) with Na, C2H5OH gives:
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  2. (CH3)3C NH2
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The following questions are multiple choice questions. Choose the most appropriate answer:
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Amines are alkyl or aryl derivatives of ammonia formed by replacement of one or more hydrogen atoms. Alkyl derivatives are called aliphatic amines and aryl derivatives are known as aromatic amines. The presence of aromatic amines can be identified by performing dye test. Aniline is the simplest example of aromatic amine. It undergoeselectrophilic substitution reactions in which -NH2 group strongly activates the aromatic ring through delocalisation of lone pair of electrons of N-atom. Aniline undergoes electrophilic substitution reactions. Ortho and para positions to the -NH2 group become centres of high electrons density. Thus, -NH2 group is ortho and para-directing and powerful activating group.
The following questions are multiple choice questions. Choose the most appropriate answer:
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  3. Lassaigne test.
  4. azo dye test.
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  2. Methyl amine.
  3. Diphenyl amine.
  4. Ethyl amine.
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  1.  Acetanilide.
  2. o-nitroacetanitide.
  3. p-nitroaniline.
  4. m-nitroanitine.
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  2. It has coordination number of 6.
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  3. $3\text{d}^1_\text{xy},3\text{d}^1_{\text{zy}},3\text{d}^1_{\text{z}^2}$
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  2. It is an octahedral, paramagnetic and outer orbital complex.
  3. It is an octahedral, paramagnetic and inner orbital complex.
  4. It is an octahedral, di magnetic and inner orbital complex.
  1. The paramagnetism of [CoF6]3- is due to.
  1. 3 electrons.
  2. 4 electrons.
  3. 2 electrons.
  4. 1 electron.
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  1. [Ni(H2O)6]3+
  2. [FeF6]3-
  3. [Co(CN)6]3-
  4. [NiCl4]2-