MCQ
$\sin \left( {4{{\tan }^{ - 1}}\frac{1}{3}} \right) = $
- A$\frac{{12}}{{25}}$
- ✓$\frac{{24}}{{25}}$
- C$\frac{1}{5}$
- Dએકપણ નહીં.
$ = \sin \left[ {2{{\tan }^{ - 1}}\frac{3}{4}} \right] = \sin {\sin ^{ - 1}}\left( {\frac{{2 \times (3/4)}}{{1 + (9/16)}}} \right)$
$ = \frac{3}{2} \times \frac{{16}}{{25}} = \frac{{24}}{{25}}$
$\left( {\because 2{{\tan }^{ - 1}}x = {{\sin }^{ - 1}}\frac{{2x}}{{1 + {x^2}}}} \right)$
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