\(R=\frac{\rho l}{A}\)

\(\therefore \quad A=\frac{\rho l}{R}\)

\(\Rightarrow \frac{A_{1}}{A_{2}}=\frac{\rho_{1}}{\rho_{2}} \times \frac{L_{1}}{I_{2}}\left(\frac{R_{2}}{R_{1}}\right)\)

\(\Rightarrow \frac{A_{1}}{A_{2}}=1 \quad\left[\because R_{1}=R_{2}, I_{1}=l_{2}\right.\) and for same

material \(\left.\rho_{1}=\rho_{2}\right]\)