તો \(\frac{{{\text{p}}_{\text{1}}^{\text{2}}}}{{{\text{2}}{{\text{m}}_{\text{1}}}}} = \frac{{p_2^2}}{{2{m_2}}}\)

\(\frac{{{p_1}}}{{{p_2}}} = \sqrt {\frac{{{m_1}}}{{{m_2}}}}  \Rightarrow \,\frac{{{\lambda _1}}}{{{\lambda _2}}} = \sqrt {\frac{{{m_1}}}{{{m_2}}}}  = \sqrt {\frac{1}{1}}  = \frac{1}{{\sqrt 2 }}\)