\(\mathrm{W}=\Delta \mathrm{KE}=0-\left(\frac{1}{2} \mathrm{mv}^2+\frac{1}{2} \mathrm{I} \omega^2\right)\)
\(\mathrm{W}=0-\frac{1}{2} \mathrm{mv}^2\left(1+\frac{\mathrm{K}^2}{\mathrm{R}^2}\right) \)
\(=-\frac{1}{2} \times 50 \times 0.4^2\left(1+\frac{1}{2}\right)=-6 \mathrm{~J}\)
Absolute work \(=+6 \mathrm{~J}\)
\(W=-6 J \quad|W|=6 J\)
$\left(g=10 \,m / s ^{2}\right.$ નો ઉપયોગ કરો.)