a
Consider the spring \(A\) is compressed by \(x\) and spring \(B\) is

compressed by \((8.75-x)\)

The compressed force is,

\(F=k x\)

\(F=300 x=400(8.75-x)\)

On solving the above equation,

\(x=5 \,cm\)

Spring \(B\) is compressed by \((8.75-5)=3.75 cm\)

Now,

\(\frac{E_{A}}{E_{B}}=\frac{\frac{1}{2} k_{A} x_{A}^{2}}{\frac{1}{2} k_{B} x_{B}^{2}}\)

\(=\frac{\frac{1}{2} \times 300 \times 5^{2}}{\frac{1}{2} \times 400 \times 3.75^{2}}\)

\(=\frac{4}{3}\)