State Ampere's circuital law. Use this law to find magnetic field due to straight infinite current carrying wire. How are the magnetic field lines different from the electrostatic field lines?
CBSE OUTSIDE DELHI - SET 2 NORTH 2016
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According to Ampers’s circuital law, “ The line integral of the magnetic field, around a closed loop, equals $\mu_{o}$ times the total current passing through the surface enclosed by that loop.”
Alternate Answer
$\oint\overrightarrow{\text{B}}.\overrightarrow{\text{d}l} = \mu_{o}\text{I}$
For the infinite current carrying wire, we get
$\text{B}.\oint\text{d}l = \mu_{o}\text{I}$
or $\text{B} 2 \pi\text{r} = \mu_{o}\text{I}$
or $\text{B} = \frac{\mu_{o}\text{I}}{2\pi\text{I}}$
The magnetic field lines form closed loops while the electric field lines originate from positive charges and end at negative charges.
Alternate Answer
$\oint\overrightarrow{\text{B}}.\overrightarrow{\text{d}l} = \mu_{o}\text{I}$
For the infinite current carrying wire, we get
$\text{B}.\oint\text{d}l = \mu_{o}\text{I}$
or $\text{B} 2 \pi\text{r} = \mu_{o}\text{I}$
or $\text{B} = \frac{\mu_{o}\text{I}}{2\pi\text{I}}$
The magnetic field lines form closed loops while the electric field lines originate from positive charges and end at negative charges.
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