Answer the following:
- In what way is diffraction from each slit related to the interference pattern in a double slit experiment?
- When a tiny circular obstacle is placed in the path of light from a distant source, a bright spot is seen at the centre of the shadow of the obstacle. Explain, why.
- How does the resolving power of a microscope depend on (i) the wavelength of the light used and (ii) the medium used between the object and the objective lens?
CBSE OUTSIDE DELHI - SET 3 BHUBNESHWAR 2015
Download our app for free and get started
The intensity of interference fringes in double slit arrangement is modulated by the diffraction pattern of each slit.
Alternate Answer
In double slit experiment, the interference pattern on the screen is actually superposition of single slit diffraction for each slit.
Waves diffracted from the edges of the circular obstacle interfere constructively at the centre of the shadow producing a bright spot.
Resolving power $\frac{2\mu\sin\theta}{1.22\lambda}.$
$\therefore$ Resolving power is inversely proportional to wavelength and directly proportional to the refractive index.
Alternate Answer
Alternate Answer
In double slit experiment, the interference pattern on the screen is actually superposition of single slit diffraction for each slit.
Waves diffracted from the edges of the circular obstacle interfere constructively at the centre of the shadow producing a bright spot.
Resolving power $\frac{2\mu\sin\theta}{1.22\lambda}.$
$\therefore$ Resolving power is inversely proportional to wavelength and directly proportional to the refractive index.
Alternate Answer
- $\text{R.P}\propto\frac{1}{\lambda}$.
- $\text{R.P}\propto\mu$.
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Prove that the power dissipated in an ideal resistor connected to an ac source is $\frac{\text{V}^2_{\text{eff}}}{\text{R}}.$View Solution
- 2An AC source of voltage $\text{V = Vm}\sin\omega\text{t}$ is applied across a series LCR circuit. Draw the phasor diagrams for this circuit, when,View Solution
- Capacitive impedance exceeds the inductive impedance.
- Inductive impedance exceeds capacitive impedance.
- 3Suppose the circuit in Exercise 7.18 has a resistance of $15\Omega.$ Obtain the average power transferred to each element of the circuit, and the total power absorbedView Solution
- 4View Solution
- Write three characteristic properties of nuclear force.
- Draw a plot of potential energy of a pair of nucleons as a function of their separation. Write two important conclusions that can be drawn from the graph.
- 5View SolutionDraw a labelled diagram of an a.c. generator. Explain briefly its principle and working.
- 6A network of four 10 $\mu$F capacitors is connected to a 500 V supply as shown in the figure. Determine theView Solution
- equivalent capacitance of the network and.
- charge on each capacitor.
- 7View SolutionWhat is Global Positioning System? Explain its working principle in brief.
- 8In series LCR circuit, the plot of $I_{max}$ vs $\omega$ is shown in Fig. Find the bandwidth and mark in the figure.View Solution
- 9View SolutionFigure shows a light bulb (B) and iron cored inductor connected to a dc battery through a switch (S).
- What will one observe when switch (S) is closed?
- How will the glow of the bulb change when the battery is replaced by an ac source of rms voltage equal to the voltage of dc battery? Justify your answer in each case.
- 10View SolutionAn inductor 200 mH, capacitor 500 µF, resistor 10Ω are connected in series with a100 V, variable frequency a.c. source. Calculate the
- Frequency at which the power factor of the circuit is unity.
- Current amplitude at this frequency.
- Q-factor.