[તારનો આડઇેદનું ક્ષેત્રણ $=0.005 \mathrm{~cm}^2 \gamma=2 \times 10^{11} \mathrm{Nm}^{-2}$ અને $\mathrm{g}=10 \mathrm{~ms}^{-2}$ ]
\(\frac{\Delta \mathrm{L}}{\mathrm{L}}=\frac{\mathrm{F}}{\mathrm{AY}}\)
\(\frac{\frac{\Delta \mathrm{L}_1}{\mathrm{~L}_1}}{\frac{\Delta \mathrm{L}_2}{\mathrm{~L}_2}}=\frac{\mathrm{F}_1}{\mathrm{~F}_2}=\frac{30}{10}=3\)