Temperature difference of $120\,^oC$ is maintained between two ends of a uniform rod $AB$ of length $2L$. Another bent rod $PQ$, of same cross-section as $AB$ and length $\frac{{3L}}{2}$, is connected across $AB$ (See figure). In steady state, temperature difference between $P$ and $Q$ will be close to .......... $^oC$
JEE MAIN 2019, Diffcult
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${T_A} - {T_B} = \frac{{{T_1} - {T_2}}}{{\frac{{8R}}{5}}} \times \frac{{3R}}{5} = \frac{3}{8} \times 120 = 45$
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