A+3B 2X,K=x What will be the equilibrium constant for the decompo… - Vidyadip

Question

$\text{A}+\text{3B}\rightleftharpoons\text{2X,}\text{K}=\text{x}$
What will be the equilibrium constant for the decomposition of 1mol of X?

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Answer

$\text{K}=\frac{[\text{X}^2]}{[\text{A}][\text{B}]^3}=\text{x}$
$\text{X}\rightleftharpoons\frac{1}{2}\text{A}+\frac{3}{2}\text{B}$
$\text{K}'=\frac{[\text{A}^{\frac{1}{2}}][\text{B}]^{\frac{3}{2}}}{[\text{X}]}$
$=\frac{1}{\sqrt{\text{K}}}=\frac{1}{\sqrt{\text{x}}}$

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