The acceleration of a particle performing S.H.M. is at a distance of $3\; cm$ from the mean position is $ 12\,cm/sec^2 $. Its time period is ..... $\sec$
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(d)$T = 2\pi \sqrt {\frac{{{\rm{Displacement}}}}{{{\rm{Acceleration}}}}} $
$ = 2\pi \sqrt {\frac{3}{{12}}} = \pi = 3.14\;\sec $
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