The capacity of a parallel plate capacitor with no dielectric substance but with a separation of $0.4 \,cm$ is $2\,\mu \,F$. The separation is reduced to half and it is filled with a dielectric substance of value $2.8$. The final capacity of the capacitor is.......$\mu \,F$
Medium
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$C = \frac{{{\varepsilon _0}KA}}{d}$ $==>$ $\frac{{{C_1}}}{{{C_2}}} = \frac{{{K_1}}}{{{K_2}}} \times \frac{{{d_2}}}{{{d_1}}}$
$\frac{2}{{{C_2}}} = \frac{1}{{2.8}} \times \frac{{(0.4/2)}}{{(0.4)}}$ $==>$ ${C_2}\, = \,11.2\,\mu \,F$
$\frac{2}{{{C_2}}} = \frac{1}{{2.8}} \times \frac{{(0.4/2)}}{{(0.4)}}$ $==>$ ${C_2}\, = \,11.2\,\mu \,F$
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