The capacity of a parallel plate condenser is $15\,\mu \,F$, when the distance between its plates is $6 \,cm$. If the distance between the plates is reduced to $2\, cm$, then the capacity of this parallel plate condenser will be......$\mu \,F$
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(c) $C \propto \frac{1}{d} \Rightarrow $$\frac{{{C_1}}}{{{C_2}}} = \frac{{{d_2}}}{{{d_1}}}$ $⇒$ $\frac{{15}}{{{C_2}}} = \frac{2}{6} ⇒ C_2 = 45\,\mu F$
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