MCQ
The displacement$-$time graphs of two moving particles make angles of $30^\circ$ and $45^\circ$ with the $x-$axis. The ratio of their velocities is:
  • $1:\sqrt{3}$
  • B
    $1:2$
  • C
    $1:1$
  • D
    $\sqrt{3}:2$

Answer

Correct option: A.
$1:\sqrt{3}$
In case $x-t$ graph the graphs are a straight line, slope of the straight line gives velocity of the particle.
Slope $=\tan \theta,$
where $\theta$ is the angle which the tangent to the curve makes with the horizontal in anti$-$clockwise direction.
$\text{v}_\text{A}=\tan30^\circ=\frac{1}{\sqrt{3}},$
$\text{v}_\text{B}=\tan45^\circ=1$
$\Rightarrow\text{v}_\text{A}:\text{v}_\text{B}=\frac{1}{\sqrt{3}}:1$
$=1:\sqrt{3}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free