The electron in the beam of a television tube move horizontally from south to north. The vertical component of the earth's magnetic field points down. The electron is deflected towards
Easy
Download our app for free and get started
(c) From Fleming’s left hand rule the force on electron is towards the east means it is deflected towards east.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
To convert galvanometer into ammeter, shunt of $0.01\,\Omega $ is used. Resistance of galvanometer coil is $50\,\Omega $ and its maximum deflection current is $20\ mA$ . Range of ammeter is
Two long parallel copper wires carry currents of $5\,A$ each in opposite directions. If the wires are separated by a distance of $0.5\,m$, then the force between the two wires is
A current of $0.1\, A$ circulates around a coil of $100$ $turns$ and having a radius equal to $5\,cm$. The magnetic field set up at the centre of the coil is ($\mu_0 = 4\pi \times 10^{-7} weber/amp-metre$)
A magnet of magnetic moment $50\,\hat i\,A{\rm{ - }}{m^2}$ is placed along the $x-$ axis in a magnetic field $\overrightarrow B = (0.5\,\hat i + 3.0\hat j)\,T.$ The torque acting on the magnet is
A rectangular loop carrying a current $i$ is placed in a uniform magnetic field $B$. The area enclosed by the loop is $A$. If there are n turns in the loop, the torque acting on the loop is given by
Magnitude of magnetic field (in $SI$ units) at the centre of a hexagonal shape coil of side $10\, cm$, $50$ turns and carrying current $I$ (Ampere) in units of $\frac{\mu_{0} I}{\pi}$ is
A cell is connected between the points $A$ and $C$ of a circular conductor $ABCD$ of centre $O$ with angle $AOC = {60^o}$. If ${B_1}$ and ${B_2}$ are the magnitudes of the magnetic fields at $O$ due to the currents in $ABC$ and $ADC$ respectively, the ratio $\frac{{{B_1}}}{{{B_2}}}$ is