To convert galvanometer into ammeter, shunt of $0.01\,\Omega $ is used. Resistance of galvanometer coil is $50\,\Omega $ and its maximum deflection current is $20\ mA$ . Range of ammeter is
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$\mathrm{i}_{\mathrm{S}} \mathrm{R}_{\mathrm{S}}=\mathrm{i}_{\mathrm{g}} \mathrm{R}_{\mathrm{g}}$
$\frac{20 \times 50}{1000}=i_{S} \times 0.01$
$\mathrm{i}_{\mathrm{S}}=100 \mathrm{\,A}$
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