the given potentiometer has its wire of resistance $10\, \Omega$. When the sliding contact is in the middle of the potentiometer wire, the potential drop across $2\, \Omega$ resistor is -
  • A$\frac{40}{11}\, {V}$
  • B$10\, {V}$
  • C$\frac{40}{9} \,{V}$
  • D$5 \,{V}$
JEE MAIN 2021, Diffcult
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