Question
The ionization constant of dimethylamine is $5.4 \times 10^{–4}$. Calculate its degree of ionization in its $0.02M$ solution. What percentage of dimethylamine is ionized if the solution is also $0.1M$ in NaOH?
| $\text{NaOH}_\text{(aq)}$ | $\leftrightarrow$ | $\text{Na}^+_\text{(aq)}$ | $+$ | $\text{OH}^-_\text{(aq)}$ |
| $0.1\text{M}$ | $0.1\text{M}$ |
| $\text{(CH}_3)_2\text{NH}$ | $+$ | $\text{H}_2\text{O}$ | $\leftrightarrow$ | $(\text{CH}_3)_2\text{NH}_2^+$ | $+$ | $\text{OH}^-$ |
| $(0.02-\text{x})$ | $\text{x}$ | $\text{x}$ | ||||
| $;0.02\text{M}$ | $;0.1\text{M}$ |
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