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Units and Measurements — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysicsUnits and Measurements3 Marks
Question
The length, breadth and thickness of a rectangular sheet of metal are $4.234m, 1.005m$, and $2.01cm$ respectively. Give the area and volume of the sheet to correct significant figures.
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Answer

Given that, length, $\mathrm{I}=4.234 \mathrm{~m}$ breadth, $\mathrm{b}=1.005 \mathrm{~m}$ thickness, $\mathrm{t}=2.01 \mathrm{~cm}=2.01 \times 10^{-2} \mathrm{~m}$ Area of the sheet $=2(\mathrm{I} \times 0$ $+\mathrm{b} \times \mathrm{t}+\mathrm{t} \times \mathrm{l})=2(4.234 \times 1.005+1.005 \times 0.0201+0.0201 \times 4.234)=2(4.3604739)=8.7209478 \mathrm{~m} 2$ As area can contain a maximum of three significant digits, therefore, rounding off, we get Area $=8.72 \mathrm{~m}^2$ Also, volume $=1 \times \mathrm{b} \times \mathrm{t}$ $V=4.234 \times 1.005 \times 0.0201=0.0855289=0.0855 \mathrm{~m}^3($ Significant Figures $=3)$

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