The magnetic field at the center of current carrying circular loop is $B _{1}$. The magnetic field at a distance of $\sqrt{3}$ times radius of the given circular loop from the center on its axis is $B_{2}$. The value of $B_{1} / B_{2}$ will be.
JEE MAIN 2022, Medium
Download our app for free and get started
$B_{1}=\frac{\mu_{0} I}{2 R}$
$B_{2}=\frac{\mu_{0} I^{2}}{2\left(R^{2}+3 R^{2}\right)^{3 / 2}}=\frac{1}{8}\left(\frac{\mu_{0} I}{2 R}\right)=\frac{B_{1}}{8}$
$\frac{B_{1}}{B_{2}}=\frac{8}{1}$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A wire of length $314\,cm$ carrying current of $14\,A$ is bent to form a circle. The magnetic moment of the coil is $........A- m ^{2}$. [Given $\left.\pi=3.14\right]$View Solution
- 2A charge $Q$ is uniformly distributed over the surface of nonconducting disc of radius $R$. The disc rotates about an axis perpendicular to its plane and passing through its centre with an angular velocity $\omega$. As a result of this rotation a magnetic field ofinduction $B$ is obtained at the centre of the disc. If we keep both the amount of charge placed on the disc and its angular velocity to be constant and vary the radius of the disc then the variation of the magnetic induction at the centre of the disc will be represented by the figureView Solution
- 3View SolutionWhich of the following particle will describe the smallest circle when projected with the same velocity perpendicular to the magnetic field ?
- 4A long straight wire is carrying current $I_1$ in $+z$ direction. The $x-y$ plane contains a closed circular loop carrying current $I_2$ and not encircling the straight wire. The force on the loop will be:View Solution
- 5A galvanometer of $50\, ohm$ resistance has $25$ divisions. A current of $4 \times 10^{-4}$ ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of $25\, volts$, it should be connected with a resistance ofView Solution
- 6A particle of mass $m$ carrying charge $q$ is accelerated by a potential difference $V$. It enters perpendicularly in a region of uniform magnetic field $B$ and executes circular arc of radius $R$, then $\frac{q}{m}$ equalsView Solution
- 7View SolutionWhat is the net force on the square coil
- 8Through two parallel wires $A$ and $B$, $10$ and $2$ $ampere$ of currents are passed respectively in opposite direction. If the wire $A$ is infinitely long and the length of the wire $B$ is $ 2\, m$, the force on the conductor $B$, which is situated at $10\, cm$ distance from $A$ will beView Solution
- 9A square coil of side $10\; cm$ consists of $20$ turns and carries a current of $12\; A$. The coil is suspended vertically and the normal to the plane of the coil makes an angle of $30^o$ with the direction of a uniform horizontal magnetic field of magnitude $0.80 \;T$. What is the magnitude of torque (in $N\;m$) experienced by the coil?View Solution
- 10A galvanometer with a resistance of $12 \,\Omega$ gives full scale deflection when a current of $3\, mA$ is passed. It is required to convert it into a voltmeter which can read up to $18\, V$. the resistance to be connected is ............... $\Omega $View Solution