The mean free path of molecules of a certain gas at $STP$ is $1500\,d$, where $d$ is the diameter of the gas molecules. While maintaining the standard pressure, the mean free path of the molecules at $373\,K$ is approximately $..........\,d$
A$1098$
B$2049$
C$750$
D$1500$
JEE MAIN 2023, Medium
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B$2049$
b Mean free path
$\lambda=\frac{ RT }{\sqrt{2} \pi d ^2 N _{ A } P }$
$\lambda \propto T$
$\frac{1500 d }{\lambda}=\frac{273}{373}$
$\lambda=2049\,d$
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