MCQ
The mole fraction of a solute in a $100$ molal aqueous solution .......... $\times 10^{-2}$

(Round off to the Nearest Integer).

[Given : Atomic masses : $H : 1.0 \,u , O : 16.0\, u ]$

  • $64$
  • B
    $52$
  • C
    $44$
  • D
    $62$

Answer

Correct option: A.
$64$
a
$100$ molal aqueous solution means there is $100$ mole solute in $1 kg =1000 gm$ water. Now,

mole-fraction of solute $=\frac{ n _{\text {solute }}}{ n _{\text {solute }}+ n _{\text {solvent }}}$

$=\frac{100}{100+\frac{1000}{18}}=\frac{1800}{2800}=0.6428$

$=64.28 \times 10^{-2}$

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