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The sliding contact $C$ is at one fourth of the length of the potentiometer wire $( AB )$ from $A$ as shown in the circuit diagram. If the resistance of the wire $AB$ is $R _0$, then the potential drop $( V )$ across the resistor $R$ is
  • A$\frac{4 V _0 R }{3 R _0+16 R }$
  • B$\frac{4 V _0 R }{3 R _0+ R }$
  • C$\frac{2 V _0 R }{4 R _0+ R }$
  • D$\frac{2 V _0 R }{2 R _0+3 R }$
NEET 2022, Medium
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