d
Escape velocity from the earth's surface $11.2\, km/sec$ है
${v_{rms}} = v_{(escape)}$ $= \sqrt {\frac{{3RT}}{M}} $
$\Rightarrow$ $T = \frac{{{{({v_{escape}})}^2} \times M}}{{3R}}$
$ = \frac{{{{(11.2 \times {{10}^3})}^2} \times (2 \times {{10}^{ - 3}})}}{{3 \times 8.31}} = 10063\; K$