The temperature of $3.00\, {mol}$ of an ideal diatomic gas is increased by $40.0^{\circ} {C}$ without changing the pressure of the gas. The molecules in the gas rotate but do not oscillate. If the ratio of change in internal energy of the gas to the amount of workdone by the gas is $\frac{{x}}{10} .$ Then the value of ${x}$ (round off to the nearest integer) is ..... . $\left(\right.$ Given $\left.{R}=8.31\, {J} {mol}^{-1} {K}^{-1}\right)$
JEE MAIN 2021, Medium
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Pressure is not changing $\Rightarrow$ isobaric process
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Two moles of an ideal monoatomic gas at ${27^o}C$ occupies a volume of $V.$ If the gas is expanded adiabatically to the volume $2V,$ then the work done by the gas will be ....... $J$ $[\gamma = 5/3,\,R = 8.31J/mol\,K]$
One mole of an ideal gas goes from an initial state $A$ to final state $B$ via two processes : It first undergoes isothermal expansion from volume $V$ to $3\, V$ and then its volume is reduced from $3\, V$ to $V$ at constant pressure. The correct $P-V$ diagram representing the two processes is
An ideal gas undergoes a polytropic given by equation $P V^n=$ constant. If molar heat capacity of gas during this process is arithmetic mean of its molar heat capacity at constant pressure and constant volume then value of $n$ is ..............