MCQ
The temperature of a gas is $ -68^\circ C$. At ...... $^oC$ temperature will the average kinetic energy of its molecules be twice that of at $ -68^\circ C$
  • $ 137$
  • B
    $ 127$
  • C
    $ 100$
  • D
    $ 105$

Answer

Correct option: A.
$ 137$
a
$\frac{{{E_2}}}{{{E_1}}} = \frac{{{T_2}}}{{{T_1}}}$

$\Rightarrow 2 = \frac{{{T_2}}}{{{T_1}}} $

$\Rightarrow {T_2} = 2{T_1}$ 

$ \Rightarrow {T_2} = 2(273 - 68) = 410K = 137^\circ C$

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