The temperature of food material in refrigerator is $4^{\circ} C$ and temperature of environment is $15^{\circ} C$. If carnot cycle is used in its working gas, then find its carnot efficiency.
AIIMS 2019, Medium
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The efficiency is given as,
$\eta=1-\frac{ T _{2}}{ T _{1}}$
Substitute the values.
$\eta=1-\frac{273+4}{273+15}$
$=0.038$
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