MCQ
The variation of potential energy of harmonic oscillator is as shown in figure. The spring constant is
- A$1 \times 10^2 N/m$
- ✓$150 N/m$
- C$0.667 \times 10^2 N/m$
- D$3 \times 10^2 N/m$
✓
Answer
Correct option: B.
$150 N/m$
b
(b)Total potential energy $= 0.04 J$
Resting potential energy $=0.01 J$
Maximum kinetic energy $=(0.04-0.01)$
$ = 0.03J = \frac{1}{2}m\;{\omega ^2}{a^2} = \frac{1}{2}k{a^2}$
$0.03 = \frac{1}{2} \times k \times {\left( {\frac{{20}}{{1000}}} \right)^2}$
$k = 0.06 \times 2500\;N/m = 150\;N/m$.
(b)Total potential energy $= 0.04 J$
Resting potential energy $=0.01 J$
Maximum kinetic energy $=(0.04-0.01)$
$ = 0.03J = \frac{1}{2}m\;{\omega ^2}{a^2} = \frac{1}{2}k{a^2}$
$0.03 = \frac{1}{2} \times k \times {\left( {\frac{{20}}{{1000}}} \right)^2}$
$k = 0.06 \times 2500\;N/m = 150\;N/m$.
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