Three bars having length $l, 2l$ and $3l$ and area of cross-section $A, 2 A$ and $3 A$ are joined rigidly end to end. Compound rod is subjected to a stretching force $F$. The increase in length of rod is (Young's modulus of material is $Y$ and bars are massless)
A$\frac{13 F l}{2 A Y}$
B$\frac{F l}{A Y}$
C$\frac{3 F l}{A Y}$
D$\frac{9 F l}{A Y}$
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C$\frac{3 F l}{A Y}$
c (c)
If extension of $\operatorname{rod}=x$
$x=x_1+x_2+x_3$
$x_1=\frac{F l}{A Y}, \quad x_2=\frac{2 F l}{2 A Y}, \quad x_3=\frac{3 F l}{3 A Y}$
So $x=\frac{3 F l}{A Y}$
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