Three capacitors are connected as shown in fig. Then the charge on capacitor $C_1$ is.....$\mu C$
Medium
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Potential at $\mathrm{A}=\frac{\mathrm{C}_{1} \mathrm{V}_{1}+\mathrm{C}_{2} \mathrm{V}_{2}+\mathrm{C}_{3} \mathrm{V}_{3}}{\mathrm{C}_{1}+\mathrm{C}_{2}+\mathrm{C}_{3}}$
$=3$ $volt$
$\therefore$ Charge of $C_{1}=Q_{1}=C_{1}(6-3)$
$=2\, \mu \mathrm{F} \times 3=6\, \mu \mathrm{C}$
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