Three perfect gases at absolute temperatures T_1 , T_2 and T_3 are mixed. The masses of molecules are m_1 , m_2 and m

Q: Three perfect gases at absolute temperatures $T_1 , T_2$ and $T_3$ are mixed. The masses of molecules are $m_1 , m_2$ and $m_3$ and the number of molecules are $n_1, n_2$ and $n_3$ respectively. Assuming no loss of energy, the final temperature of the mixture is

c Number of moles of first gas $=\frac{n_{1}}{N_{A}}$ Number of moles of second gas $=\frac{n_{2}}{N_{A}}$ Number of moles of third gas $=\frac{n_{3}}{N_{A}}$ If there is no loss of energy then $\mathrm{P}_{1} \mathrm{V}_{1}+\mathrm{P}_{2} \mathrm{V}_{2}+\mathrm{P}_{3} \mathrm{V}_{3}=\mathrm{PV}$ $\frac{n_{1}}{N_{A}} R T_{1}+\frac{n_{2}}{N_{A}} R T_{2}+\frac{n_{3}}{N_{A}} R T_{3}$ $=\frac{n_{1}+n_{2}+n_{3}}{N_{A}} R T_{m i x} \quad T_{\operatorname{mix}}=\frac{n_{1} T_{1}+n_{2} T_{2}+n_{3} T_{3}}{n_{1}+n_{2}+n_{3}}$

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

Three perfect gases at absolute temperatures $T_1 , T_2$ and $T_3$ are mixed. The masses of molecules are $m_1 , m_2$ and $m_3$ and the number of molecules are $n_1, n_2$ and $n_3$ respectively. Assuming no loss of energy, the final temperature of the mixture is

A$\frac{{{n_1}^2{T_1}^2 + {n_2}^2{T_2}^2 + {n_3}^2{T_3}^2}}{{{n_1}{T_1} + {n_2}{T_2} + {n_3}{T_3}}}$
B$\frac{{{T_1} + {T_2} + {T_3}}}{3}$
C$\;\frac{{{n_1}{T_1} + {n_2}{T_2} + {n_3}{T_3}}}{{{n_1} + {n_2} + {n_3}}}$
D$\;\frac{{{n_1}{T_1}^2 + {n_2}{T_2}^2 + {n_3}{T_3}^2}}{{{n_1}{T_1} + {n_2}{T_2} + {n_3}{T_3}}}$

AIEEE 2011, Medium

STD 11 Science
JEE
STD 11 - 12 . kinetic theory of gases
Physics

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Download App

Download our appand get started for free

Similar Questions

Download our app
and get started for free