MCQ
Three simple harmonic motions in the same direction having the same amplitude a and same period are superposed. If each differs in phase from the next by ${45^o}$, then
  • A
    The resultant amplitude is $(1 + \sqrt {2)} a$
  • B
    The phase of the resultant motion relative to the first is $90^°$
  • C
    The energy associated with the resulting motion is $(3 + 2\sqrt {2)} $ times the energy associated with any single motion
  • Both (a) and (c)

Answer

Correct option: D.
Both (a) and (c)
d
(d) Let simple harmonic motions be represented by

${y_1} = a\sin \,\left( {\omega \,t - \frac{\pi }{4}} \right)$; ${y_2} = a\sin \omega \,t$ and

${y_3} = a\sin \,\left( {\omega \,t + \frac{\pi }{4}} \right)$.

On superimposing, resultant SHM will be $y = a\;\left[ {\sin \,\left( {\omega \,t - \frac{\pi }{4}} \right) + \sin \omega \,t + \sin \,\left( {\omega \,t + \frac{\pi }{4}} \right)} \right]$

$ = a\;\left[ {2\sin \omega \,t\cos \frac{\pi }{4} + \sin \omega \,t} \right]$

$ = a\;[\sqrt 2 \sin \omega t + \sin \omega t] = a\;(1 + \sqrt 2 )\sin \omega \,t$

Resultant amplitude =$(1 + \sqrt 2 )a$

Energy is $S.H.M.$ $\propto$ (Amplitude)$^2$

 $\frac{{{E_{{\rm{Resultant}}}}}}{{{E_{{\rm{Single}}}}}} = {\left( {\frac{A}{a}} \right)^2} = {(\sqrt 2 + 1)^2} = (3 + 2\sqrt 2 )$

==> ${E_{{\rm{Resultant}}}} = (3 + 2\sqrt 2 ){E_{{\rm{Single}}}}$

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