c
Let masses are kept at points \(A, B\) and \(C\) where \(P\) denotes the centre of mass of the system which lies at a distance \(x\) from point \(A.\)

Using \(\quad x=\frac{m_{1} r_{1}+m_{2} r_{2}+m_{3} r_{3}}{m_{1}+m_{2}+m_{3}}\)

\(\therefore \quad x=\frac{m \times 0+m \times 1+m \times 2}{m+m+m}=\frac{3 m}{3 m}=1\)

Thus the centre of mass of the system lies at distance of \(1\) unit away from point \(\mathrm{A}\)

om the line joining the masses i.e line \(ABC\)

Hence the centre of mass of the system lies at \((2,2)\)