Two capacitors $C_1$ and $C_2$ are charged to $120\ V$ and $200\ V$ respectively. It is found that connecting them together the potential on each one can be made zero. Then
JEE MAIN 2013, Medium
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For potential to be made zero, after connection
$120 \mathrm{C}_{1}=200 \mathrm{C}_{2} \quad\left[\because C=\frac{q}{v}\right]$
$\Rightarrow \quad 3 C_{1}=5 C_{2}$
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