Two capacitors of capacities $2 {C}$ and ${C}$ are joined in parallel and charged up to potential ${V}$. The battery is removed and the capacitor of capacity $C$ is filled completely with a medium of dielectric constant ${K}$. The potential difference across the capacitors will now be
JEE MAIN 2021, Medium
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$V_{C}=\frac{2 C V+C V}{K C+2 C}$
$V_{C}=\frac{3 V}{K+2}$
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