Question
Two circles with centres O and O' intersect at two points A and B. A line PQ is drawn parallel to OO' through A or B, intersecting the circles at P and Q. Prove that PQ = 2OO'.
Draw a line PQ parallel to OO' through B, OX perpendicular to PQ, O'Y perpendicular to PQ, join all. We know that perpendicular drawn from the centre to the chord, bisects the chord.$\therefore$ PX = XB and YQ = BYGenerate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.


Given: side BC < side AD, side BC || side AD, side BA = side CD
To prove: ∠ABC ≅ ∠DCB
Construction: Draw seg BP ⊥ side AD, A – P – D
seg CQ ⊥ side AD, A – Q – D

