Question
Two cross roads, each of width 5 m , run at right angles through the centre of a rectangular park of length 70 m and breadth 45 m parallel to its sides. Find the area of the roads. Also, find the cost of constructing the roads at the rate of Rs. 105 per $m ^2$.

Answer




Let $A B C D$ be the rectangular park then $E F G H$ and $I J K L$ the two rectangular roads with width 5 m .

Length of the rectangular park $A D=70 cm$

Breadth of the rectangular park $C D=45 m$

Area of the rectangular park $=$ Length $\times$ Breadth $=70 m \times 45 m=3150 m^2$

Area of the road $EFGH =70 m \times 5 m=350 m^2$

Area of the road JKIL $=45 m \times 5 m=225 m^2$

Clearly area of MNOP is common to the two roads.

Thus, Area of MNOP $=5 m \times 5 m=25 m^2$

Hence,

Area of the roads $=$ Area $(E F G H)+$ Area(JKIL) - Area(MNOP $)$

$=(350+225) m^2-25 m^2=550 m^2$

Again, it is given that the cost of constructing the roads $=$ Rs. 105 per $m ^2$

Therefore,

Cost of constructing $550 m^2$ area of the roads $=$ Rs. $(105 \times 550)$

= Rs. 57750

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