$=2 \mathrm{m} \omega$
$\alpha \mathrm{m}$
$\mathrm{m}_{\mathrm{A}}=\mathrm{m}$ $\mathrm{m}_{\mathrm{B}}=\frac{\mathrm{m}}{2}$
$\frac{b_{A}}{b_{B}}=\frac{1}{2}$

Statement $I :$ A second's pendulum has a time period of $1$ second.
Statement $II :$ It takes precisely one second to move between the two extreme positions.
In the light of the above statements, choose the correct answer from the options given below:
