Question
Two exactly identical pendulums are oscillating with amplitudes 2cm and 6cm. Calculate the ratio of their energies of oscillation.
$\therefore$ Ratio of total energy = 1 : 9
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$\text{Q = mc(T}_2-\text{T}_1),\text{l}_{\text{t}}=\text{l}_0[1+\alpha(\text{T}_2-\text{T}_1)]$ and $\text{PV = nRT}.$