Two metallic spheres of radii 1,, cm and 3,, cm are given, charges of -1 times {10^{

Q: Two metallic spheres of radii $1\,\, cm$ and $3\,\, cm$ are given, charges of $-1$$ \times {10^{ - 2}}$ $C$ and $5$$ \times {10^{ - 2}}\,C$ respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is

c When the given metallic spheres are connected by a conducting wire, charge will flow till both the spheres acquire a common potential which is given by Common potential, $V =\frac{q_{1}+q_{2}}{C_{1}+C_{2}}=\frac{-1 \times 10^{-2}+5 \times 10^{-2}}{4 \pi \varepsilon_{0} R_{1}+4 \pi \varepsilon_{0} R_{2}}$ $=\frac{4 \times 10^{-2}}{4 \pi \varepsilon_{0}\left(1 \times 10^{-2}+3 \times 10^{-2}\right)}$ $=\frac{4 \times 10^{-2}}{4 \pi \varepsilon_{0} \times 4 \times 10^{-2}}.........(i)$ $\therefore $ Final charge on the bigger sphere $=4 \pi \varepsilon_{0} \times 3 \times 10^{-2} \times \frac{4 \times 10^{-2}}{4 \pi \varepsilon_{0} \times 4 \times 10^{-2}}(\mathrm{Using}(\mathrm{i}))$ $=3 \times 10^{-2} \mathrm\,{C}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Two metallic spheres of radii $1\,\, cm$ and $3\,\, cm$ are given, charges of $-1$$ \times {10^{ - 2}}$ $C$ and $5$$ \times {10^{ - 2}}\,C$ respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is

A$1$$ \times {10^{ - 2}}\,C$
B$2$$ \times {10^{ - 2}}\,C$
C$3$$ \times {10^{ - 2}}\,C$
D$4$$ \times {10^{ - 2}}\,C$

AIPMT 2012, Medium

STD 11 Science
NEET
STD 12 - 2. Electric potential and capacitance
Physics

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