a
$(a, b, c)$ Let $V$ be the volume of shperes.
For equilibrium of $A$ :
$T+v d_A g=V D_f g$
$\therefore T=V_g\left(d_f-d_A\right) \cdots(1)$
$f \text { or } T > 0, d_f > d_A \text { or } d_A < d_f$
$(a)$ is the correct option
For equilibrium of $B$ :
$T+V d_f g=V d_B g$
$\therefore T=V_g\left(d_B \cdot d_f\right) \cdots$
$F \text { or } T > 0, d_B > d_f$
$(b)$ is the correct option
$\text { From (1) and (2) Vg }\left(d_f-d_A\right)=V g\left(d_B-d_f\right)$
$\therefore d_f-d_A=d_B-d_f$
$\therefore 2 d_f=d_A+d_B$
