Two strings with circular cross section and made of same material… - Vidyadip

MCQ

Two strings with circular cross section and made of same material, are stretched to have same amount of tension. A transverse wave is then made to pass through both the strings. The velocity of the wave in the first string having the radius of cross section $R$ is $v_{1}$, and that in the other string having radius of cross section $R / 2$ is $\mathrm{v}_{2}$. Then $\frac{\mathrm{v}_{2}}{\mathrm{v}_{1}}=$

A
$\sqrt{2}$
✓
2
C
8
D
4

✓

Answer

Correct option: B.

2

(B) 2
$v=\sqrt{\frac{T}{\mu}}=\sqrt{\frac{\mathrm{T}}{\mathrm{f} \pi \mathrm{R}^{2}}}$
$\frac{\mathrm{v}_{2}}{\mathrm{v}_{1}}=\frac{\mathrm{R}_{1}}{\mathrm{R}_{2}}=2$

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